Make your own free website on

Perpendicular Bisector

(note: it may take a few minutes to load Sketchpad)
Sorry, this page requires a Java-compatible web browser. If you're using a recent version of your browser, be sure to check its Preferences or Options to make sure that Java content is enabled.
  • Drag P until PA=PB

  • How many different places may the point P be placed so that PA=PB?

  • Make a conjecture to generalize the locus of points so that PA=PB. Then click the "Show Answer" button to see that locus.

  • [Ohter JavaSketchpad Pages by Ryan]

    [Ryan's Homepage]