P(a card between 5 and Jack) = | # of cards between 5 and Jack | = | 20 | = | 2 | = .40 |
# of cards that may be dealt | 50 | 5 |
P(a card between 3 and 4) = | 0 | = 0 |
50 |
There are four Queens and four 7's, so there are 8 cards out of a total of 52 that may be selected. Thus P(Queen or 7) = 8 / 52. | |